Statistics- A pollster selected 4 of 7 available people

Quiz #2`Name________________________Section No. _____________(5%)1. A pollster selected 4 of 7 available people. How many different groups of 4 arepossible?10%2. Your firm has a contract to make 2000 staff uniforms for a fast –food retailer. Theheights of the staff are normally distributed with a mean of 70 inches and a standarddeviation of 3 inches. What percentage of uniforms will have to fit staff shorter than67inches? What percentage will have to be suitable for staff taller than 76 inches.?a) 16% & 2.5%b) 68% & 95%c) 32% & 5%(15%)3. The industry standards suggest that 20% of new vehicles require warranty servicewithin the first year. A dealer sold 20 Nissans yesterday. Use equation for BinomialProbability for part a) and Table II for part b) & c). Show work!a) What is the probability that none of these vehicles requires warranty service? Use theBinomial equation for P(X=0).b) What is the probability that exactly one of these vehicles requires warranty service?c) Determine the probability 3 or more of these vehicles require warranty service.d) Compute the mean and std. dev. of this probability distribution.(15%)4. Allen & Associates write weekend trip insurance at a very nominal charge. Recordsshow that the probability a motorist will have an accident during the weekend and willfile a claim is quite small (.0005). Suppose Alden wrote 400 policies for the forthcomingweekend. Compute the probability that exactly two claims will be filed using the equationfor Poisson Probability.Note: The symbol λ is the mean (expected value) which we used as μ = np. So λ isnothing more than the mean number of occurrences (successes = np) in a particularinterval.Get the probability that the number of claims is at least 3 from Poisson Tables.(10%)5. Given a standard normal distribution, determine the following. Show Table Valuesused in each part.a) P(Z<1.4)b) P(Z>1.4)c) P(Z< -1.4)d) P( – 0.50<Z<1.0)e) P(0.50<Z<1.5)15%6. A company is considering offering child care for their employees. They wish toestimate the mean weekly child-care cost of their employees. A sample of 10 employeesreveals the following amounts spent last week in dollars.101 97 93 103 100 93 99 90 102 96Develop a 95% confidence interval for the population mean. Interpret the result.x =??, S=??, t / 2 =??, Range of = (??)15%7. The National Safety Council reported that 56 % of American turnpike drivers aremen. A sample of 256 cars traveling southbound on the New Jersey Turnpikeyesterday revealed that 165 were driven by men. At the .01 significance level, can weconclude that a larger proportion of men were driving on the New Jersey Turnpikethan the national statistics indicate? First, state H0 & HaHO: ??, Ha: ??a) Is this a Z or t test?b) Test Statistic = ?c) Critical value = ?d) p-value = ?e) Reject Ho: (yes or no)15%8. Given the hypothesis: H0: μ≥18 & Ha: μ<18, a random sample of five resulted inthe following values: 17, 18, 20, 16, & 15. Using the .01 significance level, can weconclude the population mean is less than 18?a) Is this a Z or t test?b) Test statistic = ?c) Critical value = ?d) Reject Ho: (yes or no)



We pride ourselves in writing quality essays


Lets Start Working

Plagiarism Free

We use anti-plagiarism software to ensure you get high-quality, unique papers. Besides, our writers have a zero plagiarism mentality

On Time Delivery

Your essay will be delivered strictly within the deadline.  If you have an urgent order, we can do it!

Money Back Guarantee

We offer warranty service, including free revisions, and a right to request a refund incase your expectations are not met!


Our Advantage

  • Say “NO” to plagiarism – FREE plagiarism report as an addition to your paper
  • The lowest prices that fit excellent quality
  • Authorship – you are the one who possesses the paper. We DO NOT re-sale or re-use any of them.


Our Freebies

  • Free Cover Page
  • Free Revisions
  • Free Reference Page
  • Free 24/7 support

Pin It on Pinterest

Share This