An electron (charge -e) moving at velocity v passes through

Need Complete formula or expression for this question:An electron (charge -e) moving at velocity v passes through two vertically stacked square parallel plates with dimension a on one side, and distance d between plates. A potential difference ΔV is applied across the plates such that the top plate is positively charged. A uniform magnetic field B is applied parrallel to the plates and transverse to the velocity of the electron to deflect the electron such that it does not go into the plates.Part A – Assuming that the magnetic field is applied only through the volume of the capacitor, what must its magnitude be if the electron strikes a screen, situated a distance L from the nearest side of the capacitor, a distance y above dead center.Dead center of the screen is where the electron would hit if its trajectory were unaltered by either the capacitor or magnetic field.Hint: Use the kinematic equations to determine the relationship between the net force and the trajectory of the electron: yf=yi+vyit+12ayt2 and xf=xi+vxit+12axt2

 

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